How much pressure is exerted on a swimmer at the bottom of 5.0 m deep swimming pool?

To calculate the pressure exerted on a swimmer at the bottom of a 5.0 m deep swimming pool, we can use the formula for hydrostatic pressure:

$$P = \rho g h$$

Where:

- P is the pressure in Pascals (Pa)

- ρ is the density of the fluid in kilograms per cubic meter (kg/m^3)

- g is the acceleration due to gravity (approximately 9.8 m/s^2)

- h is the depth of the fluid in meters (m)

In this case, the fluid is water, which has a density of approximately 1000 kg/m^3. The depth of the water is 5.0 m.

Substituting these values into the formula, we get:

$$P = (1000 \text{ kg/m}^3)(9.8 \text{ m/s}^2)(5.0 \text{ m})$$

$$P = 49,000 \text{ Pa}$$

Therefore, the pressure exerted on the swimmer at the bottom of the 5.0 m deep swimming pool is 49,000 Pa.