How many gallons of water in a 27 foot round pool and 48 inches deep?

`Volume of water = π * r^2 * h`

Radius = 27 feet / 2 = 13.5 feet

Height = 48 inches / 12 = 4 feet

`Volume of water = 3.14 * (13.5)^2 * 4`

`Volume of water = 3.14 * 182.25 * 4`

`Volume of water = 2304.2 cubic feet`

To convert cubic feet to gallons, multiply the volume by 7.48:

`Volume of water = 2304.2 * 7.48`

`Volume of water = 17,236.45 gallons`

Therefore, a 27-foot round pool with a depth of 48 inches holds approximately 17,237 gallons of water.