How many gallons of water would an round by 48 deep swimming pool hold?

The volume of a cylinder is given by the formula V = πr^2h, where r is the radius of the cylinder and h is its height. In this case, the radius of the pool is 24 feet and the height is 48 feet. So, the volume of the pool is:

V = π(24)^2(48)

= 34,557.52 cubic feet

We need to convert this volume to gallons, since the question asks for the number of gallons of water the pool would hold. There are 7.48 gallons in one cubic foot, so the number of gallons of water the pool would hold is:

34,557.52 cubic feet * 7.48 gallons/cubic foot

= 258,852.6 gallons

Therefore, the round by 48 deep swimming pool would hold approximately 258,853 gallons of water.