How many gallons of ware ire in a 18 foot round pool that is 48 inches high?

V = π(r^2)h

Where:

- V is the volume of water in gallons

- r is the radius of the pool in feet

- h is the height of the pool in feet

In this case, the pool is 18 feet in diameter, so the radius r is 18/2 = 9 feet. The pool is 48 inches high, which is equivalent to 48/12 = 4 feet.

Plugging these values into the formula, we get:

V = π(9^2)4

V = π x 81 x 4

V = 1017.88 cubic feet

To convert cubic feet to gallons, we multiply by 7.48. So the volume of water in the pool is:

V = 1017.88 x 7.48

V = 7592.53 gallons

Therefore, there are approximately 7,593 gallons of water in an 18-foot round pool that is 48 inches high.