How many gallons of water are in an easy set above ground 18 foot diameter x 52 inch d 51k?

$$V = \pi r^2 h$$

where:

- V is the volume in cubic feet

- r is the radius of the pool in feet

- h is the height of the pool in feet

To calculate the volume of an 18-foot diameter x 52-inch deep pool, we need to first convert the diameter to feet:

$$18 \text{ ft} \times \frac{1 \text{ft}}{12 \text{in}} = 1.5 \text{ ft}$$

Now we can plug the values into the formula:

$$V = \pi (1.5 \text{ ft})^2 (52 \text{ in})$$

$$V = \pi (2.25 \text{ ft}^2) (4.33 \text{ ft})$$

$$V = 30.53 \text{ ft}^3$$

To convert cubic feet to gallons, we multiply by 7.48:

$$V = 30.53 \text{ ft}^3 \times 7.48 \text{ gal/ft}^3$$

$$V = 227.81 \text{ gal}$$

Therefore, an easy set above ground 18 foot diameter x 52 inch deep pool holds approximately 228 gallons of water.